Approximation Test-2 (Rounding off to Integers)

Answer: Option E

Explanation

Given,

$\sqrt{\text{8650}}\text{ =?}$

It can be approximated as

$\sqrt{\text{8650}}\text{ =?}$

= $\sqrt{8650}=\sqrt{8100+550}$

[ nearer to 90]

=90 ≈ 93

Hence, Option E is correct.

Answer: Option D

Explanation

Given,

$1\frac{4}{7}+7\frac{1}{3}+3\frac{3}{5}=?$

It can be approximated as

$$\begin{gathered} 1\frac{4}{7}+7\frac{1}{3}+3\frac{3}{5}=? \\ =(1+7+3)+(\frac{4}{7}+\frac{1}{3}+\frac{3}{5}) \\ =\left(11\right)+\left(\frac{60+35+3}{105}\right) \\ = 11+\left(\frac{158}{105}\right) \end{gathered}$$

= 11+1.5

= 12.5 ≈ 13

Hence, Option D is correct.

Answer: Option C

Explanation

Given,

$7\frac{3}{11}\times 626-7\frac{2}{3}=?$

It can be approximated as

$\frac{80}{11}\times 626-\frac{23}{3}=\frac{80}{11}\times 616-\frac{24}{3}$

= 80×56-8=4480-8

= 4472 ≈ 4495

Hence, Option C is correct.

Answer: Option D

Explanation

Given,

$\text{1439}÷\text{16}\times \text{14.99+}\sqrt{\text{(228)}}=?$

It can be approximated as

$\text{1440}÷\text{15}\times \text{15+15}$

[As per the BODMAS order]

= 96×15+15

= 1440+15

= 1455 ≈ 1465

Hence, Option D is correct.

Answer: Option D

Explanation

Given,

(11.92)²+(16.01)²=?²×(3.85)²

It can be approximated as

(11.92)²+(16.01)²=?²×(3.85)²

= (12)²+(16)²≈(?)²×(4)²

= 144+256=(?)²×16

= 400= (?)²×16

= $\frac{400}{16}$=(?)²

=25=(?)²

= 5

Hence, Option D is correct.