Approximation Test-4 (Approximation of decimal figures)

Answer: Option C

Explanation

Given,

41% of 401-250.17=?-77% of 910

It can be approximated as

40% of 600-250=?-80% of 900

= $\frac{40}{100}$×600-250=?-$\frac{80}{100}$×900

= 240-250=?-720

= -10+720

= 710 ≈ 700

Hence, Option C is correct.

Answer: Option A

Explanation

Given,

40.005% of 439.998 +?% of 655.011 = 228.5

It can be approximated as

40% of 440 +?% of 650 = 230

= $\frac{40\times 400}{100}+?\% of 650=230$

= 176+?% of 650 =230

= ?% of 650 =230-176

= ? =$\frac{54\times 100}{650}=\frac{5400}{650}$

= 8.30 ≈ 8

Hence, Option A is correct.

Answer: Option E

Explanation

Given,

6894.986 + 5025.005 + 600.020 =?

It can be approximated as

6894.986 + 5025.005 + 600.020 =?

$$\begin{gathered} \begin{array}{l}\text{6894.986 + 5025.005 +. 600.020}\\ \downarrow \downarrow \downarrow \\ \text{ 7000 + 5000 + 600}\end{array} \\ = 12600-12520 \end{gathered}$$

Hence, Option E is correct.

Answer: Option B

Explanation

Given,

${\left(21.5\% of 999\right)}^{\frac{1}{3}}+(43\% of 601{)}^{\frac{1}{2}}$

It can be approximated as

${\left(22\% of 1000\right)}^{\frac{1}{3}}+(\frac{40}{100}\times {600}^{}{)}^{\frac{1}{2}}=?$

 $$\begin{gathered} \begin{array}{l}\text{?= }{\left(\text{220}\right)}^{\text{1/3}}+{\left(240\right)}^{1/2}\\ \\ \text{= }{\left(\text{216}\right)}^{\text{1/3}}+{\left(225\right)}^{1/2}\\ \\ \text{= 6+15 ? }\end{array} \\ \text{= 21}\approx \text{22} \end{gathered}$$

Hence, Option B is correct.

Answer: Option E

Explanation

Given,

12959.998÷18.010=?

It can be approximated as

$\begin{array}{l}\text{12959.998}÷\text{12960}\\ \downarrow \downarrow \\ 12960÷18\end{array}$

= 720

Hence, option E is correct.