Average Test-2 (Finding average of specified numbers)

Answer: Option B

Explanation

According to the formula,

The average of first 'n' natural numbers

$=\left(\frac{\mathrm{n}+1}{2}\right)$

Here,

  n=51

∴ Required average$=\frac{51+1}{2}=\frac{52}{2}$

= 26

Hence, Option B is correct.

Answer: Option B

Explanation

Given averages 2, 4, 6, 8, 10, 11, 12, 14.

According to the formula,

The average of first 'n' even numbers =(n+1)

Here, n=7

∴ Required average =(7+1)=8

Hence, Option B is correct.

Answer: Option B

Explanation

According to the formula,

The average of first 'n' odd numbers= n

Here, n=9

∴ Required average= 9

Hence, Option B is correct.

Answer: Option B

Explanation

According to the formula,

The average of consecutive numbers= $\frac{\mathrm{First} \mathrm{number} +\mathrm{Last} \mathrm{number}}{2}$

Here,

First number= 1 and Last number =53

∴ Required average=$\frac{1+53}{2}=\frac{54}{2}=27$

Hence, Option B is correct.

Answer: Option D

Explanation

Given averages 4, 7, 10, 13,...., 28, 31.

The difference between any two numbers written in continuos sequence is 3.

we know the formula

The average of consecutive number =$\frac{\mathrm{First} \mathrm{number}+\mathrm{Last} \mathrm{number}}{2}$

Here, First number= 4 and Last number =31

∴ Required average

$$\begin{gathered} =\frac{4+31}{2} \\ =\frac{35}{2} \\ =17.5 \end{gathered}$$

Hence, Option D is correct.