Average Test-2 (Finding average of specified numbers)

Answer: Option E

Explanation

According to the formula,

The average of 1 to n odd numbers =$\frac{\mathrm{Last} \mathrm{odd} \mathrm{number}+1}{2}$

Here, The last odd number= 45

∴ Average of 1 to 45 odd numbers =$\frac{45+1}{2}=\frac{46}{2}=23$

Again, According to the formula,

The average of 1 to n even numbers=$\frac{\mathrm{Last} \mathrm{even} \mathrm{number}+2}{2}$

Here, Last even number = 44

∴ Average of 1 to 44 even numbers =$\frac{44+2}{2}=\frac{46}{2}=23$

Hence, Option E is correct.

Answer: Option B

Explanation

Given, 

The average of 9 consecutive positive integers = 63

So, it is middle value of the consecutive numbers.

∴ Fifth number = 63

Smallest number= 59

Largest number = 67

∴ Required product = 59×67=3953.

Hence, Option B is correct.

Answer: Option E

Explanation

let four consecutive even numbers be x-2, x, x+2, x+4.

According to the question,

= x-2+x+x+2+x+4=4×51

= 4x+4=204

= x= 50

So, P=48, Q=50, R=52, S=54

∴ The product of P and R

= P×R

= 48×52= 2496

Hence, Option E is correct.

Answer: Option C

Explanation

According to the question

The average of 8 consecutive odd numbers =$\frac{656}{8}$= 82

∴ Fourth number = 82-1=81

First number = 75

Average of 4 even numbers = 87

∴ Second even number = 87-1= 86

Second largest even number = 88

∴ Required sum =75+88=163

Hence, Option C is correct.

Answer: Option B

Explanation

According to the question,

Mean of set A=$\frac{376}{8}=47$

Lowest number of second set = 47+15= 62

∴ Required sum = 62+63+64+65+66

= 320

Hence, Option B is correct.