Simplification for IBPS PO test 4-Solved questions with detailed explanations for SSC, IBPS PO, SBI PO, RRB, RBI, CSE, CGL, CHSL, CDA, CSE, UPSC

6)

What will come in place of question mark (?) in the following questions

$6 \frac{2}{3} + 3 \frac{3}{5} + 3 \frac{5}{6} = ?$

[Andhra Bank (PO), 2009]

A)
15
B)
$15 \frac{11}{20}$
C)
$14 \frac{1}{10}$
D)
14
E)
None of these

Answer: Option C

Explanation

In this above question

add this by separatong integral part and fractional part.

$= (6 + 3 + 3) + (\frac{2}{3} + \frac{3}{5} + \frac{5}{6}) = (12) + (\frac{20 + 18 + 25}{30}) = 12 + (\frac{63}{30}) = 12 \frac{21}{10} o r 14 \frac{1}{10}$

Hence, Option C is correct.

Discussion

7)

$5 \frac{17}{18} \times 2 \frac{10}{11} \div \frac{8}{3} = ?$

[UK GBO, 2008]

A)
$34 \frac{3}{11}$
B)
$12 \frac{49}{66}$
C)
$71 \frac{1}{3}$
D)
$55 \frac{7}{8}$
E)
None of these

Answer: Option C

Explanation

We follow the rule of BODMAS to solve the expression

$= \frac{107}{8} \times \frac{32}{11} \div \frac{8}{33} = \frac{107}{8} \times \frac{32}{11} \times \frac{33}{8} = \frac{107}{18} \times 12 = \frac{214}{3} = 71 \frac{1}{3}$

Hence, Option C is correct.

Discussion

8)

$\frac{1}{2} + \frac{1}{4} + \frac{3}{4} + \frac{2}{3} = ?$

[Bank of Baroda (PO), 2008]

A)
$2 \frac{1}{5}$
B)
$\frac{1}{16}$
C)
$2 \frac{1}{16}$
D)
$2 \frac{1}{6}$
E)
None of these

Answer: Option C

Explanation

From the above question,

We take L.C.M of 2,4,4 and 3 is 12

$= \frac{6 + 3 + 9 + 8}{12} = \frac{26}{12} = 2 \frac{1}{6}$

Hence, Option C is correct.

Discussion

9)

$5 \frac{1}{4} + 6 \frac{2}{3} + 7 \frac{1}{6} = ?$

[SBI (PO), 2008]

A)
19.5
B)
$19 \frac{11}{12}$
C)
$19 \frac{1}{12}$
D)
19
E)
None of these

Answer: Option E

Explanation

Here, we separate the integral part and fractional part.

$= (5 + 6 + 7) + (\frac{1}{4} + \frac{2}{3} + \frac{1}{6}) = (18) + (\frac{3 + 4 \times 2 + 2}{12}) = 18 + \frac{13}{12} = 18 + 1 \frac{1}{12} = 19 \frac{1}{12}$

Hence, Option E is correct.

Discussion

10)

$4 \frac{5}{6} - 5 \frac{5}{9} = ? - 2 \frac{1}{3} + \frac{11}{18}$

[UBI (PO), 2001]

A)
$\frac{3}{4}$
B)
$2 \frac{1}{18}$
C)
$1 \frac{7}{9}$
D)
$1 \frac{11}{18}$
E)
None of these

Answer: Option D

Explanation

Here,

$= \frac{29}{6} - \frac{50}{9} = ? - \frac{7}{3} + \frac{11}{18} = \frac{87 - 100}{18} = ? - \frac{42 + 11}{18} = \frac{- 13}{18} + \frac{31}{18} = ? = \frac{18}{18} = ? o r 1 = ?$

Hence, Option D is correct.

Discussion

Simplification-Test 4 (Based on Fractions/Square roots and Cube roots)

Answer: Option C

Answer: Option C

Answer: Option C

Answer: Option E

Answer: Option D