Simplification for IBPS PO test 8-Solved questions with detailed explanations for SSC, IBPS PO, SBI PO, RRB, RBI, CSE, CGL, CHSL, CDA, CSE, UPSC

11)

Raman's present age is three times his daughter's present age and nine-thirteenth of his mother's present age. The sum of the present ages of all of them is 125 yr . What is the difference between the Raman's daughter's present age and Raman's mother's present age?

[Allahabad Bank (PO), 2011]

A)
45 yr
B)
40 yr
C)
50 yr
D)
Cannot be determined
E)
None of these

Answer: Option D

Explanation

Given that,

$\begin{array}{l} Raman's present age = x years \\ ∴ His daughter's present age = \frac{x}{3} years \\ His mother's present age = \frac{13 x}{9} years \\ ∴ x + \frac{x}{3} + \frac{13 x}{9} = 125 \\ \Rightarrow \frac{9 x + 3 x + 13 x}{9} = 125 \\ \Rightarrow 25 x = 125 \times 9 \\ \Rightarrow x = \frac{125 \times 9}{25} = 45 \\ ∴ Required difference \\ = \frac{13 x}{9} - \frac{x}{3} \\ = \frac{13 x - 3 x}{9} = 10 \frac{x}{9} \\ = \frac{10}{9} \times 45 = 50 y r \end{array}$

Hence, Option D is correct.

Discussion

12)

Harshita bought 20 pens, 8 packets of wax colours, 6 calculatos and 7 pencil boxes. The price of one pen is ₹ 7. One packet of wax colour is ₹ 22, one calculator is ₹ 175 and one pencil box is ₹ 14 more than the combined price of one pen and one packet of wax colour. How much amount did Harshita pay to the shop keeper?

[IBPS Bank PDIMT CWE, 2011]

A)
₹ 1381
B)
₹ 1667
C)
₹ 1815
D)
₹ 1572
E)
None of these

Discussion

13)

Raju runs 1250 m on Monday and Friday. Other days, he runs 1500 m except for Sunday (He does not run on Sunday). How many kilometre will he run in 3 weeks (first day starting from Monday)

[Indian Overseas Bank (PO), 2011]

A)
12.5 km
B)
8.5 km
C)
20.5 km
D)
25.5 km
E)
None of these

Answer: Option D

Explanation

$\begin{array}{l} Here, total meters run by Raju in week. \\ Days Monday Tuesday Wednesday \\ Meter 1250 1500 1500 \\ Thursday Friday Saturday \\ 1500 1250 1500 \\ Total distance covered by him in 1 week \\ = 1250 \times 2 + 1500 \times 4 \\ = 2500 + 6000 \\ = 8500m \\ Total distance covered by him in 3 weeks \\ = 3 \times 8500= 25500 m \\ =25.5km \end{array}$

Hence, option D is correct.

Discussion

14)

Fifty three per cent of a number is 358 less than the square of 26. What is the value of three fourth of 23 percent of that number?

[Corporation Bank (PO), 2011]

A)
101
B)
109.5
C)
113
D)
103.5
E)
None of these

Answer: Option D

Explanation

Let the number be 'x'

$\begin{array}{l} Then, 53% of x {= (26)}^{2} - 358. \\ \Rightarrow \frac{53}{100} \times x = 676 - 358 \\ \Rightarrow x = \frac{318 \times 100}{53} = 600 \\ S o, \frac{3}{4} \times 23 % \times 600 \end{array} \Rightarrow \frac{3}{4} \times \frac{23}{100} \times 600 = 69 \times 1 .5 = 103 .5$

Hence, Option D is correct.

Discussion

15)

The cost of five chairs and three tables is ₹ 3110. Cost of one chair is ₹ 210 less than cost of one table. What is the cost of two tables and two chairs?

[BOB (PO), 2011]

A)
₹ 1660
B)
₹ 1860
C)
₹ 2600
D)
Cannot be determined
E)
None of these

Answer: Option A

Explanation

$\begin{array}{l} If the CP of 1 chair is Rs x, then CP of \\ 1 table= Rs (x + 210) \\ ∴ 5 x +3(x + 210)=3110 \\ \Rightarrow 5 x + 3 x + 630 = 3110 \\ \Rightarrow 8 x = 3110 - 630 = 2480 \\ ∴ x = \frac{2480}{8} = 310 \\ :. CP of two tables and two chairs \\ = 2(x + x + 210)= 4 x + 420 \\ =4 \times 310+ 420= Rs1660. \end{array}$

Hence, option A is correct.

Discussion

Simplification-Test 8 (Based on Algebraic formulae/Statement simplifications)

Answer: Option D

Answer: Option B

Answer: Option D

Answer: Option D

Answer: Option A