Simplification-Test 1 (Based on VBODMAS rule)

Answer: Option E

Explanation

Here, 24×114÷19-x=312÷13

We apply the BODMAS rule to solve this expression

⇒ 24×6-x=24

⇒ 24×6-24=x

⇒ 24(6-1)=x

⇒ 24×5=x

⇒ x=120

Hence, Option E is correct.

Answer: Option A

Explanation

Here, $\frac{5^2\times 14+1450}{5}=1998÷x$

We apply the bodmas rule to solve this expression

$$\begin{gathered} \Rightarrow \frac{350+1450}{5}=1998÷x \\ \Rightarrow \frac{{\displaystyle 1800}}{{\displaystyle 5}}=1998÷x \\ \therefore x=5.55 \end{gathered}$$

Hence, Option A is correct.

Answer: Option A

Explanation

In this question,

 $$\begin{gathered} \Rightarrow 1\frac{1}{3}+2\frac{1}{6}-3\frac{1}{9}=1÷x \\ \Rightarrow \frac{4}{3}+\frac{13}{6}-\frac{28}{9}=1÷x \\ \Rightarrow \frac{24+39-56}{18}=1÷x \\ \Rightarrow \frac{7}{18}=1÷x \\ \Rightarrow x=\frac{18}{7}=2\frac{4}{7} \end{gathered}$$

Hence, Option A is correct.

Answer: Option D

Explanation

In this question,

$$\begin{gathered} \Rightarrow 1246+\sqrt[4]{256}=\left(x^2+19\frac{1}{3}\right)\times 15 \\ \Rightarrow 1246+4=\left(x^2+\frac{58}{8}\right)\times 15 \\ \Rightarrow \frac{1250}{15}=x^2+\frac{58}{3} \\ \Rightarrow \frac{250}{3}-\frac{58}{3}=x^2 \\ \Rightarrow \frac{192}{3}=x^2 \\ \Rightarrow x=\sqrt{64}=8 \end{gathered}$$

Hence, Option D is correct.

Answer: Option D

Explanation

$\begin{array}{l}\text{In this question,}\\ \\ \Rightarrow \frac{9}{13}\text{ of 221+1}\frac{4}{9}\text{ of 379 = 241 +?}\\ \\ \Rightarrow 9\times 17+13\times 42=241+?\\ \\ \Rightarrow 153+546=241+?\\ \\ \Rightarrow x=458\end{array}$

Hence, Option D is correct.