Simplification-Test 3 (Based on Decimals)

Answer: Option D

Explanation

Here, We follow the rule of bodmas as well as decimals.

 $$\begin{gathered} \sqrt{625.04}\times 16.96+136.001÷17 \\ = \sqrt{625.04}\times 16.96+8 \\ =25\times 16.96+8 \\ =424.013+8 \\ =432.013\approx 433 \end{gathered}$$

Hence, Option D is correct.

Answer: Option E

Explanation

In this above question

we apply bodmas rule,

⇒ $3\frac{1}{4}+2+\frac{1}{2}-\left(1+\frac{5}{6}\right)=\frac{(?{)}^2}{10}+1+\frac{5}{12}$

Or, add the integral part and fractional part separately.

$$\begin{gathered} = (3+2-1)+(\frac{1}{4}+\frac{1}{2}-\frac{5}{6}) \\ = \frac{(?{)}^2}{10}+1+\frac{5}{12} \\ = \left(4\right)+\left(\frac{3+6-10}{12}\right)=\frac{(?{)}^2}{10}+1+\frac{5}{12} \\ = (4-1)+\left(-\frac{1}{12}-\frac{5}{12}\right)=\frac{(?{)}^2}{10} \\ =3-\frac{6}{12}=\frac{(?{)}^2}{10} \\ = 3-\frac{1}{2}=\frac{(?{)}^2}{10} \\ = \frac{5}{2}\times 10=(?{)}^2 \\ = 25=(?{)}^2 \\ =\sqrt{25}=? \\ =?=5 \end{gathered}$$

Hence, Option E is correct.

Answer: Option A

Explanation

In this above question,

We add fractional and integral part separately.

$$\begin{gathered} =1+\frac{1}{4}+1+\frac{1}{6}-\left(1+\frac{1}{8}\right)=?+1+\frac{1}{12} \\ = (1+1-1-1)+\left(\frac{1}{4}+\frac{1}{6}-\frac{1}{8}-\frac{1}{12}\right)=? \\ = ? =0+\frac{6+4-3-2}{24} \\ = ? =\frac{5}{24} \end{gathered}$$

Hence, Option A is correct.

Answer: Option A

Explanation

Here, we add both integral and fractional part separately and follow the order of BODMAS.

$$\begin{gathered} = 4+\frac{1}{2}-\left(2+\frac{5}{6}\right)+1+\frac{7}{12}=? \\ = (4-2+1)+\left(\frac{-5}{6}+\frac{7}{12}+\frac{1}{2}\right)=? \\ = ? =3+\left(\frac{-10+7+6}{12}\right)=3+\frac{1}{4}=\frac{13}{4} \\ = 3\frac{1}{4} \end{gathered}$$

Hence, Option A is correct.

Answer: Option A

Explanation

Here,

$$\begin{gathered} = \frac{3}{8}\times \frac{4}{9}\times 1092 \\ = \frac{12}{72}\times 1092=12\times 15.16 \\ = 181.92=182 \end{gathered}$$

Hence, Option A is correct.