Simplification: Basic Concept of VBODMAS, Types of simplification questions, Tips and Tricks to solve simplification questions
Posted on : 03-01-2019 Posted by : Admin

Simplification for IBPS clerk, Simplification tricks, Simplification in mathematics, Simplification examples, SImplification formulae, VBODMAS rule,

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Basic concept of VBODMAS

In mathematics, to arrive at final answer, we need to solve various types of expressions. For solving these expressions, we need different techniques. Simplification is one of the basic techniques to solve the given complex expression into a simpler form.

Generally, an arithmetic expression involves various mathematical operations like addition, subtraction, division, multiplication arranged in various types of brackets. These expressions must be solved in a specific defined order from left to right. The mnemonic of this order is VBODMAS. It is also known as VBODMAS rule.

V is vinculum or bar

B is brackets

O is order of exponent roots

D is division

M is multiplication

A is addition

S is subtraction

Even the operations in various brackets must be solved in an order. The order of simplifying brackets is as follows,

  1. Small circular brackets, Ci ( )
  2. Middle curly brackets, Cu { }
  3. Big square brackets, Sq [ ]

So the sequence of solving the brackets is ViCiCuSq, Let us understand it better with the below example,

 

Types of Simplification questions

There are many types of simplification questions. A few of them are explained below,

Type 1: Based on VBODMAS rule

These types of questions strictly follow VBODMAS rule. And if the rule is followed correctly, we can arrive at the answer quickly and easily.

For example:

Question: What will come in th eplace of question mark in the below given question?

1246+(256)4=?2+1913×15

Solution:

 1246+2564=x2+1913×151246+4=x2+588×15125015=x2+583 2503-583=x21923=x2 x=64=8

Type 2: Based on Decimal

Addition and subtraction of decimals

While performing addition or subtraction of the decimals, each of the given decimal numbers re written under each other such that the decimal points line in one column. The numbers on either side of the decimal point must be arranged carefully. Finally the addition and subtraction is performed conventionally.

For example:

Question: What will come in place of question mark in the below given question?

6435.9+7546.4+1203.5=?

Solution: The numbers on either side of the decimal point must be arranged carefully

      6435 . 9                        7546 . 4               +1203 . 5      15185 . 8


Multiplication of decimals

While performing multiplication, the given decimal numbers are multiplied without considering the decimal point. Finally in the product the decimal point is marked from right hand side to as many places as the total sum of the number of decimal places in multiplier and multiplicand together.

For example:

Question: What will come in place of question mark in the below given question?

2.5×3.25=?

Solution: The decimal point is marked from right hand side to as many places as the total sum of the number of decimal places in multiplier and multiplicand together.

2.5×3.25=8.125


Division of decimals

While performing division, the dividend and the divisor both are multiplied by a suitable multiple of 10 to convert the divisor into to a whole number and then the conventional division is carried out.

For example:

Question: What will come in place of question mark in the below given question?

(833.25  384.45) ÷ 24 =? 

Solution: The dividend and the divisor both are multiplied by a suitable multiple of 10 to convert the divisor into to a whole number and then the conventional division is carried out.

(833.25  384.45)24448.8)24=18.7

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Type 3: Based on fractions

Fractions are integral parts of a whole number. In a fraction the number above the line is called numerator and the number below the line is called denominator. Sometimes the fractions may also be in the form of mixed fractions which first need to be converted into a fraction and then simplified.

For simplifying the fractions, the integral part and the fraction are added separately. And VBODMAS rule is followed.

For example:

Question: What will come in place of question mark in the below given question?

412-256=?-1712

Solution: For simplifying the fractions, the integral part and the fraction are added separately. And VBODMAS rule is followed.

= 4+12-2+56+1+712=?= (4-2+1)+-56+712+12=?= ? =3+-10+7+612=3+14=134= 314

Type 4: Based on Square, Square root, Cube, Cube root

Square: Is the number is multiplies by itself, then the product of this multiplication is called square of that number

For example:

Question: Find the value of 182?

Solution:

18 × 18 = 324


Square root: The square root of a number is that number, whose square is equal to the given number. It is represented by √ placed on the given number.

For example:

Question: What will come in place of question mark in the below given question?

360225×2+379=?

Solution:

360450 + 379            = 360 + 379450            = 739450            = 289=17


Cube: If the number is multiplied two times with itself, then the result of this multiplication is called the cube of that number.

For example:

Question: Find the value of 83?

Solution:

8 × 8 × 8 = 512


Cube root: The cube root of a number is that number, whose cube is equal to the given number. It is represented by 3√ placed on the given number.

For example:

Question: What will come in place of question mark in the below given question?

8043573=?

Solution:

8043573=933 x13=93

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Type 5: Based on Surds and Indices

These types of questions strictly follow VBODMAS rule. And if the rule is followed correctly, we can arrive at the answer quickly and easily.

For example:

Question: What will come in place of question mark in the below given question?

[(57+7 )×(47 + 87)](19)2=?

Solution:

[(57+7)×(47+87)(19)2= ? [20×7 + 280 + 28 + 56]361 =? [420 + 84]361 =? 504361 = ?? = 143

Type 6: Based on Percentages

While performing addition or subtraction of the decimals, each of the given decimal numbers re written under each other such that the decimal points line in one column. The numbers on either side of the decimal point must be arranged carefully. Finally the addition and subtraction is performed conventionally.

For example:

Question: What will come in place of question mark?

?% of 555 + 28% of 444 = 202.02

Solution:

x100×555+28100×444=202.025.55x+28×4.44=202.025.55x = 202.02 -124.325.55x = 77.7x=77.75.55 =14


While performing multiplication, the given decimal numbers are multiplied without considering the decimal point. Finally in the product the decimal point is marked from right hand side to as many places as the total sum of the number of decimal places in multiplier and multiplicand together.

For example:

Question: What will come in place of question mark?

14% of 250× ?% of 150=840

Solution:

14100×250×x%of150=840   [ taking x at the place of ?]14100×250×x100×150=8403500100×x100×150=840x=840×100150×35=24×100100=16


While performing division, the dividend and the divisor both are multiplied by a suitable multiple of 10 to convert the divisor into to a whole number and then the conventional division is carried out.

For example:

Question: What will come in place of question mark?

64.5%of800+36.4% of1500=(?)2+38

Solution:

64.5100×800+36.4100×1500=(?)2+3864.5×8 + 36.4×15 = (?)2+38516 + 546 = (?)2+38?2= 516+ 54638 = 106238    ?=1024=32

Type 7: Based on algebraic formulae

In each of these questions, there is a related algebraic expression. First we need to find the related algebraic expression and then simply the question based on the expression. Below table lists out the important algebraic expressions,

  1. (a+b)2=a2+b2+2ab
  2. (a-b)2=a2+b2-2ab
  3. (a+b)(a-b)=a2-b2
  4. (a+b)2+(a-b)2=2(a2+b2)
  5. (a+b)2-(a-b)2=4ab
  6. (a+b)3= a3+3a2b+3ab2+b3
  7. (a-b)3= a3-3a2b+3ab2-b3
  8. a3+b3=(a+b)( a2+b2-ab)
  9. a3-b3=(a-b)( a2+b2+ab)

For example:

Question: What will come in place of question mark?

662-342=?

Solution:

This is similar to,

 [a2b2= (a+ b)(ab)]So, = 662342= (66 + 34)×(6634)= 100×32 = 3200

Type 8: Based on Statements

The questions of type are given in statement form. In this type of questions first we need to form an expression from the given statements and try to simplify the expression.

For example:

Question: On the annual day, sweets were to be distributed equally amongst 600 children of the school. But on that particular day, 120 children remained absent. Thus, each child got 2 extra sweets. How many sweets was each child originally supposed to get?

Solution

Number of extra sweets    = 2×480 = 960These sweets were to be distributedamong 120 children. Number of sweets to be given to eachchild on originally = 960120 = 8Hence, option A is correct.

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