If the positions of the digits of a two digit number are interchanged, the number obtained is smaller than the original number by 27. If the digits of the number are in the ratio of 1 : 2, what is the original number?
[United Bank of India (POl), 2009]
Explanation
let the original number be 10x+y
Now, by interchanging the position of the digits of the number, we get 10y+x
Accoding to the question,
(10x+y)−(10y+x)=27
If y=3, x=6
Then, (10×6)+3 = 63
Hence option B is correct.
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