In a two digit number, the digit in the unit's place is twice the digit in the ten's place and the number obtained by interchanging the digits is more than the original number by 27. What is 50% of the original number?
[SBI (PO) , 2005]
Explanation
Let the original number be 10x+y and y=2x
The number obtained by interchanging the position of the digits =10y+x
⇒ 10x+y+27=10y+x
⇒ 9x-9y=-27
⇒ y-x=3 or 2x-x=3
⇒ y=3×2=6
∴ x=3,y=6
So, 50% of this number is 18.
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