There are two numbers such that the sum of twice the first number and thrice the second number is 100 and the sum of thrice the sum first number and twice the second number is 120. Which is the larger number?
[Corporation Bank (PO), 2009]
Explanation
Let the two numbers be x and y
and 2x+3y=100
Again, 3x+2y=120
2x+3y=100 ---×2 (multiply by '2')
3x+2y=120 ---×3 (multiply by '3')
we get
4x+6y=200 ---Eq(1)
9x+6y=360 ---Eq(2)
By subracting Eq(1) and Eq(2) we get
⇒ -5x=-160
⇒ x=32, y=12
Hence, larger number is 32.
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