Let the one even number be x'

Then, another even number is (x+2)

Now, x(x+2)=3248

or x²+2x-3248=0

⇒ x²+58x-56x-3248=0    (by splitting the middle term)

⇒ x(x-56)+58(x-56)=0

⇒ (x-58)(x-56)=0

⇒ x=56

∴ Larger nummber is x+2 or 56+2=58

Hence, Option A is correct.