Let the first even number be 'x'

Then, second number is x+2

Again, x²+(x+2)²=6500

or x²+(x+2)²+4+4x=6500

⇒ 2x²+4x+4=6500

⇒ x²+2x+2=3250

⇒ x²+2x-3250=0

⇒ x²+58x-56x-3250=0   (by splitting the middle term)

⇒ x(x-56)+58(x-56)=0

⇒ x=56

∴ smaller number is 56.

Hence, Option d is correct.