Practice Test Discussion

If the numerator of a fraction is increased by 200% and the denominator is increased by 350%. The resultant fraction is $\frac{5}{12}$ . what was the original fraction?

[IOB (PO), 2009]

$\frac{5}{9}$

$\frac{5}{8}$

$\frac{7}{12}$

$\frac{11}{12}$

None of these

Explanation

Let the original fraction be $\frac{x}{y}$

Then, numerator= $x + x \times \frac{200}{100} = 3 x$

And denominator= $y + y \times \frac{350}{100} o r \frac{450 y}{100}$

So, fraction = $\frac{N u m e r a t o r}{D e n o m i n a t o r} = \frac{3 x \times 100}{450 y} = \frac{2 x}{3 y}$

Now, = $\frac{2 x}{3 y} = \frac{5}{12}, \frac{x}{y} = \frac{15}{24} = \frac{5}{8}$ .

Hence, Option B is correct.

Arithmetics

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