The difference between two numbers is 18 and their HCF and LCM are 6 and 168, respectively. What is the sum of squares of the two numbers?
[RBI, 2015]
Explanation
Let one number be 'x'
Then, another number is x+18
Now, product of two numbers= HCF×LCM
⇒ x×(x+18)=6×168
⇒ x²×18x=1008
⇒ x²×18x-1008=0
⇒ x²×42x-24x-1008=0
⇒ x(x-24)+42(x-24)=0
⇒ x=24
∴ Another number is 42.
Required sum =(24)²+(42)²
=576+1764=2340.
Hence, Option D is correct.
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