The sum of a number and its reciprocal is one-fifth of 26. What is the sum of that number and its square?
Explanation
Let the number be 'x', Then its reciprocal is
Given that,
= 5(x²+1)=26x
= 5x²+5-26=0 [By factorising]
= 5x²-25x-x+5=0
= 5x(x-5)-1(x-5)=0
= (5x-1)(x-5)=0
= x=5 or
Hence, Option C is correct.
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