Practice Test Discussion

A number of two-digit has 3 for its unit digit and the sum of the digit is $\frac{2}{11}$ of the number itself. The number is

None of these

Explanation

Let the ten's digit be 'x'

Then, number (10x+3)+ sum of digits = (x+3)

So,

⇒ (x+3)= $\frac{2}{11}$ (10x+3)

⇒ (11x+33)=(20x+6)

= (11x-20x)=6-33

= -9x=-27

= x=3

∴ the number 33.

Hence, Option D is correct.

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