In a two digit number, if it is known that its unit digit exceeds its tenth's place digit by 2 and product of the given number and sum of the digit is equal to 144, then the number is
Explanation
Let the ten's digit be 'x'
Then, unit's digit= x+2
= 10x+(x+2)=11x+2
Sum of digits =x+(x+2)=2x+2
= (11x+2)(2x+2)=144
= 22x²+22x-140=0
= 11x²+13x-70=0
= (x-2)(11x+35)=0
= x=2
∴The required number = 11x+2=24
Hence, Option C is correct.
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