Here,

$$\begin{gathered} =\frac{{\left(216\right)}^{{\displaystyle \frac{1}{3}}}\times {26}^4\times {\left(39\right)}^4}{{\left(12\right)}^4\times 3\times 2^{-3}}={13}^x \\ =\frac{6\times 2^4\times 3^4\times {13}^8}{{\left(2\times 6\right)}^4\times 3\times 2^{-2}}={13}^x \\ =\frac{6\times 6^4\times {13}^8}{6\times 6^4}={13}^x \\ ={13}^8=13 \\ =x=8 \end{gathered}$$

Hence, Option A is correct.