$\begin{array}{l}\text{Here,}\\ \\ \text{92}\times \text{576}÷\text{2}\sqrt{\text{1296}}+{\text{(?)}}^{\text{3}}\text{+}\sqrt{\text{49}}\\ \\ \text{We can also write it as}\\ \\ \text{92}\times \text{576}÷\text{2}\times {\text{36 = (?)}}^{\text{3}}\text{+}\sqrt{\text{49}}\\ \\ \Rightarrow \text{ 92}\times \text{576}÷{\text{72 = (?)}}^{\text{3}}\text{+}\sqrt{\text{49}}\\ \\ \text{Here, we apply the BODMAS rule.}\\ \\ \text{So, 92}\times {\text{8 = (?)}}^{\text{3}}\text{+ 7}\\ \\ \Rightarrow \text{ 736}-{\text{7 = (?)}}^{\text{3}}\\ \\ \Rightarrow \text{ (?) =}{}^3\sqrt{\text{729}}\text{ = 9}\end{array}$

Hence, Option C is correct.