Here,

$$\begin{gathered} = {\left(0.125\right)}^3÷{\left(0.25\right)}^2\times {\left(0.5\right)}^2={\left(0.5\right)}^{7-?} \\ = {\left\{{\left(0.5\right)}^3\right\}}^3+{\left(0.5\right)}^{2\times 2}\times {\left(0.5\right)}^2={\left(0.5\right)}^{7-?} \\ ={\left(0.5\right)}^{9-4}\times {\left(0.5\right)}^2={\left(0.5\right)}^{7-?} \\ ={\left(0.5\right)}^5\times {\left(0.5\right)}^2={\left(0.5\right)}^{7-?} \\ = {\left(0.5\right)}^7={\left(0.5\right)}^{7-?} \\ =7-?=7 \\ =?=0 \end{gathered}$$

Hence, Option D is correct.