$\begin{array}{l}\text{Here, }\\ \Rightarrow {{\left(2\right)}^{3\times }}^{1.3}\times {\left(2^2\right)}^{x0.6}\times {\left(2\right)}^{4\times 0.2}=2^{?}\\ \\ \Rightarrow 2^{3.9+1.2+0.8}=2^{?}\\ \\ [\because m^x\times m^y\times m^z=m^{x+y+z}]\\ \\ \Rightarrow 2^{5.9}=2^{?}\\ \\ \Rightarrow ?=5.9\end{array}$

Hence, option C is correct.