From a group of men and women, 15 women leave from it. Then, there are 2 men for each women. After this, 45 men leave. Then, there are 5 women for each men. Find the double of the number of women in the beginning.
Explanation
According to the question,
Let at present, there are 'C' men, then number of women = 5c
Before the men had left,
Number of men = c+45 and
Number of women = 5c
∴ c+45=2×5c
= 9c=45
= c = =5
Hence, number of women in the beginning
= 5c+15=5×5+15
= 25+15 =40
∴ Double of the women = 40×2=80
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