In this above question

Given that,

Let the number be 'z'

$$\begin{gathered} =\left(\frac{3}{5}\right)\left(\frac{2}{5}\right)z-\left(\frac{4}{5}\right)\left(\frac{1}{4}\right)z=5 \\ =\left(\frac{3}{10}\right)z-\left(\frac{1}{5}\right)z=5 \\ =z\left(\frac{3}{10}-\frac{1}{5}\right)=5 \\ =z\left(\frac{1}{10}\right)=5 \\ z=\frac{10\times 5}{1}=50 \end{gathered}$$

Hence, Option D is correct.