Given,

$\sqrt{\text{2498}}\times \sqrt{\text{626}}÷\sqrt{\text{99}}\text{ = ?}$

It can be approximated as

$\sqrt{\text{2500}}\times \sqrt{\text{625}}÷\sqrt{100}\text{ = ?}$

= 50×25÷10

= 50×2.5

= 125

$\left[\because \sqrt{2500}=50, \sqrt{625}=25\right]$

Hence, Option E is correct.