Practice Test Discussion

What approximate value should come in place of the question mark (?) in the given questions?

423.62-269.21÷(11.9% of 78)=?

[IBPS (PO), 2014]

525

455

645

395

275

Explanation

Given,

423.62-269.21÷(11.9% of 78)=?

It can be approximated as

425-270÷(12% of 80)=?

= $425 - 270 \div (\frac{12 \times 80}{100}) = ?$

= 425-270÷10

= 425-27

= 398 ≈ 395

Hence, Option D is correct.

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