Given,

${\text{95}}^{3.7}÷{95}^{0.99890}={95}^{?}$

It can also be written as

${\text{95}}^{3.7}÷{95}^{0.99890}={95}^{?}$

[Put ?=x]

$$\begin{gathered} = {95}^{3.7}÷{95}^{0.998}={95}^x \\ = {95}^{3.7-0.9989}={95}^x \\ = {95}^{2.7011}={95}^x \end{gathered}$$

(since the bases are the same,

set the exponents equal)

= x= 2.7011

=2.7011 ≈ 2.7

Hence, Option E is correct.