Given set of scores=48, 47, 64, 91, 72, 68, 93

We know the formula,

 $\mathrm{Average} \left(\mathrm{A}\right)=\frac{\mathrm{Sum} \mathrm{of} \mathrm{given} \mathrm{values} \left(\mathrm{S}\right)}{\mathrm{Total} \mathrm{number} \mathrm{of} \mathrm{values} \left(\mathrm{N}\right)}$

 Here,

 Sum of given values(S)

= 48+47+64+91+72+68+93

= 483

Total number of values(N)= 7

Substituting these values we get (A),

 $= \frac{483}{7}=69$

Hence, Option C is correct.