According to the question,

1 man= 2 woman= 3 boys

 ∴ 1 man + 1 woman + 1 boy

$=\left(3+\frac{3}{2}+1\right)boys =\frac{11}{2} boys$

Here,

M₁ = 3, D₁ =88

M₂ = $\frac{11}{2}$, D₂ = ?

So according to the formula,

     M₁ D₁ = M₂ D₂

∴  Required no. of days can becalculated as below,

$$\begin{gathered} 3\times 88=\frac{11}{2}\times D_2 \\ {D}_2=\frac{3\times 2\times 88}{11} \\ =3\times 2\times 8=48 days \end{gathered}$$

Hence option D is correct.