Here,

M₁ = 6, T₁ =16, W₂ =1

M₂ = 8, T₂ = ?, W₁ = 1

So according to the formula,

     M₁ D₁ W₂ = M₂ D₂ W₁

 $$\begin{gathered} \therefore 6\times 16\times 1=8\times T_2\times 1 \\ {T}_2=\frac{16\times 6}{8}=2\times 6=12 hrs \end{gathered}$$

 So, 8 boys complete the same work in 12 hours

 Hence option C is the correct.