16 children and 24 men complete a certain work in 18 days. If each child takes twice the time taken by a man to finish the work, in how many days will 24 men finish the same work?
Explanation
Given in the question,
2 children= 1 man
∴ (16 children + 24 men)= (8+24) men = 32 men
We shall use the formula, M1 D1 W2 = M2 D2 W1
Here,
M1 = 32, D1 =18, W1 =1,
M2 = 24, D2 = ?, W2 = 1,
⇒ 32×18×1=24×D2×1
D2
Hence option B is the correct.
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